Yak Sbi Clerk 2018 Coaching Solar Daytime Four - Speed, Fourth Dimension As Well As Distance (Shortcuts & Practise Tests)

Hello friends, today nosotros shall larn shortcut tricks almost Speed, Time & Distance. This is too 1 of the of import too easiest aptitude topics for banking, insurance too other competitive exams, where yous volition acquire a compulsory question. But the work is, people tend to lose marks inwards Speed, Time too Distance topic due to negligence. I volition explicate how this happens. In the examination hall, nosotros volition last inwards a hurry mood to reply equally many questions equally possible. So nosotros won't read the query properly. You demand to check, in WHICH UNITS they asked the answer. Some times they may enquire the reply inwards Kmph, but yous acquire your publish inwards Mps. To confuse you, they volition give both the numbers inwards options. So, instead of converting the units,  nosotros hurriedly score the selection of the families number, all the same assuming that our reply is correct. So yous demand to crosscheck the units earlier marker the answer. Okay, let's acquire into the details of today's lesson Speed, Time too Distance.  Let's laid about amongst basic formulas. Write these downwardly inwards your notebook. Hope yous are already maintaining a carve upward notebook for these lessons.

Speed, Time too Distance Shortcuts

Speed, Time & Distance Formulas

1. Speed = Distance / Time  [S = D/T]

2. Distance = Speed x Time  [D=S x T]

3. Time = Distance / Speed [T=D/S]

4. The units of speed = Kilometres per hr (Kmph) or Metres per 2d (Mps).

5. Kmph x (5/18) = Mps

6. Mps x (18/5) = Kmph

7. If 2 bodies are inwards drive too their speeds are 'X' units too 'Y' units, the resultant speed (which is called relative speed) is to last taken inwards the house of 'S inwards the outset iii formulas above.

Relative speed is

• X + Y  if they motion inwards contrary direction 
• X-Y if they motion inwards same management

8. If a develop has to cross whatever only about other body, it has to comprehend a distance which is equal to the amount of its ain length too that of the other torso which it has to cross too this full is to last taken inwards the house of 'D' inwards the outset iii formulas. In illustration of the length of the other torso is negligible, solely the length of the develop is to last taken.

9. Average speed = Total distance covered / Total fourth dimension taken

10. In 2 cases of equal distances, the average speed = 2AB/(A+B)   where H5N1 too B are the speeds.

11. In iii cases of equal distances, the average speed = 3ABC (AB + BC + CA)  where A, B too C are the speeds.

12. In 4 cases of equal distances, the average speed = 4ABCD / (ABC + BCD + CDA + DAB) where A, B, C too D are the speeds.

13. If a human covers a distance at 2 dissimilar speeds amongst belatedly too / or early on times,

The distance = (Difference inwards given belatedly or early on times inwards hours x Product of the speeds)  / Difference of the speeds

=  (∆t × π s)/∆s

too right speed required  = (∆t × π s)/(S2 × ∆t ±t1 ×∆s)

Note : Here yous should role '+' if t1 is early on necktie too '-' if t1 is belatedly time.

14. If the average speeds of a develop including stoppages too excluding stoppages are given, the fourth dimension inwards minutes for which the develop stops for hr = (Difference inwards speeds x 60) / Higher speed

15. If a human walking at N/D of his park speed inwards T minutes belatedly or early, thence the park fourth dimension taken yesteryear him = (N/(N D)) ×T

16. If a develop crosses 2 objects of 'l' too 'L' units inwards length inwards 't' too 'T' times, thence the speed =  (l L)/(t T) too the length of the develop = (t(l L)/(t T)) - l

17. Down current speed (DS) is the speed at which an object moves along with the time period of water.

DS = X + Y, where X = Speed of the object inwards all the same (calm) H2O too Y = speed of the water

18. Upstream speed (US) is the speed at which an object moves against  the time period of the water.

USA = X-Y, where X = Speed of the object inwards all the same (calm) H2O too Y = speed of the water

19. Speed or Velocity of a human or a boat inwards all the same H2O = X = (DS + US)  / 2

20. Speed or Velocity of Water or Flow or Stream or Current = Y = (DS - US) / 2

Now let's operate amongst problems. As usual, I volition explicate 1 work per model too part 3 problems of the same model for your practice.

Speed, Time too Distance : Examples & Practice Problems 

Model 1 :

1. The speed of a automobile is xl kmph. What distance tin it comprehend inwards ix seconds ?
1. 96 mts
2. 100 mts
3. 108 mts
4. 120 mts
5. None of these 

Solution :

* If yous detect closely, inwards query they gave the speed inwards Kmph. But inwards reply options, they gave the speed inwards mts. So yous should convert Kmph into Mph.

Note : To convert Kmph into Mph, yous demand to multiply it amongst 5/18

Here south = xl kmph

t = ix sec

d = s.t = xl x (5/18) x ix = 100 Mph

Let's operate amongst only about other problem.

2. The speed of a automobile is lx kmph. What distance tin it comprehend inwards 13.5 seconds ?

1. 96 mts
2. 100 mts
3. 108 mts
4. 120 mts
5. None of these 

Solution :

= lx x (5/18) x 13.5

Note : Decimal points ever ho-hum downwardly your calculations. So to take decimal betoken from 13.5, Multiply Numerator too Denominator amongst 10.

= lx x (5/180) x 135   

= 225

Practice Problems on Model 1 

1. The speed of a automobile is 36 kmph. What distance tin it comprehend inwards 9.6 seconds ?
1. 96 mts
2. 100 mts
3. 108 mts
4. 120 mts
5. None of these 
2. The speed of a automobile is lxxx kmph. What distance tin it comprehend inwards 5.4 seconds ?
1. 96 mts
2. 100 mts
3. 108 mts
4. 120 mts
5. None of these

Model 2 :

1. A develop tin comprehend a distance of 243 km inwards 3 hours. What is its speed inwards meters / 2d ?
1. 12.5
2. 18
3. 20
4. 22.5
5. None of these 

Solution :

south = d/t

Here too the speed of the automobile given inwards Kmph but asked the reply inwards Mts. So,

= (243/3) x (5/18)

= 22.5 mps

Practice Problems on Model 2 :

1. A develop tin comprehend a distance of 324 km inwards 4 hours. What is its speed inwards meters / 2d ?
1. 12.5
2. 18
3. 20
4. 22.5
5. None of these 
2. A develop tin comprehend a distance of 360 km inwards v hours. What is its speed inwards meters / 2d ?
1. 1.5
2. 18
3. 20
4. 22.5
5. None of these
3. A develop tin comprehend a distance of 280.8 km inwards 4 hrs twenty min. What is its speed inwards meters / 2d ?
1. 12.5
2. 18
3. 20
4. 22.5
5. None of these 

Model 3 :

1. In what fourth dimension tin a automobile comprehend a distance of 360 km at 12 1/2 mps ?
1. 5 hrs
2. 8 hrs
3. 10 hrs
4. 20 hrs
5. None of these 

Solution :

t = d/s

(360 x 2 x 5) / (25 x 18) = 8 hrs

Practice Problems on Model 3

1. In what fourth dimension tin a automobile comprehend a distance of 270 km at fifteen mps ?
1. 5 hrs
2. 8 hrs
3. 10 hrs
4. 20 hrs
5. None of these 
2. In what fourth dimension tin a automobile comprehend a distance of 1440 km at twenty mps ?
1. 5 hrs
2. 8 hrs
3. 10 hrs
4. 20 hrs
5. None of these 
3. In what fourth dimension tin a automobile comprehend a distance of 960 km at xviii mps ?
1. 5 hrs
2. 8 hrs 
3. 10 hrs
4. 20 hrs
5. None of these 

Model 4 :

1. A develop 250 1000 long is running at 45 kmph. In what fourth dimension tin it top a tree ?
1. 15 sec
2. 20 sec
3. 30 sec
4. 24 sec
5. None of these 

Solution :

t = d/s

= (250 x 18) / (45 x 5) = twenty sec

Practice problems on Model 4 :

1. A develop 300 1000 long is running at 36 kmph. In what fourth dimension tin it top a pole ?
1. 15 sec
2. 20 sec
3. 30 sec
4. 24 sec
5. None of these 
2. A develop 375 1000 long is running at xc kmph. In what fourth dimension tin it top a human ?
1. 15 sec
2. 20 sec
3. 30 sec
4. 24 sec
5. None of these 
3. A develop 336 1000 long is running at 42 kmph. In what fourth dimension tin it top a railway signal ?
1. 18 sec
2. 20 sec
3. 22.5 sec
4. 24 sec
5. None of these 

Model 5 :

1. A develop 600 1000 long moves at 36 kmph. In what fourth dimension tin it top a duad of 1200 1000 long ?
1. 2 min
2. 2.5 min
3. 3 min
4. 4 min
5. None of these 

Solution :

t = d/s

= ((600+1200) x 18) / (36x5)

= 180 sec 

= 3 min

Practice Problems on Model 5

1. A develop 300 1000 long moves at 72 kmph. In what fourth dimension tin it top a duad of 420m long ?
1. 36 sec
2. 48 sec
3. 1 min
4. 1.2 min
5. None of these 
2. A develop 400 1000 long moves at 63 kmph. In what fourth dimension tin it top a duad of 440 1000 long ?
1. 2 min
2. 48 sec
3. 1 min
4. 1.2 min
5. None of these 
3. A develop 500 1000 long moves at 54 kmph. In what fourth dimension tin it top a duad of 2.2 km long ?
1. 2 min
2. 2.5 min
3. 3 min
4. 4 min
5. None of these 

Model 6 :

1. A develop moving at a speed of 45 mps takes 12 sec to top a human running at the charge per unit of measurement of v mps inwards the same direction. The length of the develop inwards meters is 
1. 350
2. 392
3. 420
4. 450
5. None of these

Solution :

d =s x t

= (45-5) x 12

= 480 m

* Speeds :

• If the Second object is moving inwards Same direction, yous demand to write Difference of speeds
• If the Second object is moving inwards Opposite direction, yous demand to write the Sum of speeds

Practice Problems on Model 6 :

1. A develop moving at a speed of xl mps takes 10 sec to top a human running at the charge per unit of measurement of v mps inwards the same direction. The length of the develop inwards meters is ?
1. 350
2. 392
3. 420
4. 450
5. None of these 
2. A develop moving at a speed of 48 mps takes 10 sec to top a human running at the charge per unit of measurement of six mps inwards the same direction. The length of the develop inwards meters is ?
1. 350
2. 392
3. 420
4. 450
5. None of these
3. A develop moving at a speed of 35 mps takes fifteen sec to top a human running at the charge per unit of measurement of v mps inwards the same direction. The length of the develop inwards meters is 
1. 350
2. 392
3. 420
4. 450
5. None of these

Model 7 :

1. Two trains running on parallel lines are 450 1000 too 350 1000 long at l kmph too xl kmph respectively. In what fourth dimension tin they top each other if they are moving inwards the same management ?
1. 4 min
2. 4 min 12 sec
3. 4 min twenty sec
4. 4 min 36 sec
5. None of these 

Solution :

t = d/s

= (800 x 18) / (10x5) = 288 sec

4mins 48 secs

Practice Problems on Model 7 

1. Two trains running on parallel lines are 450 1000 too 470 1000 long at 52 kmph respectively. In what fourth dimension tin they top each other if they are moving inwards the same management ? 
1. 4 min
2. 4 min 12 sec
3. 4 min twenty sec
4. 4 min 36 sec
5. None of these 
2. Two trains running on parallel lines are 300 1000 too 350 1000 long at 49 kmph too xl kmph respectively. In what fourth dimension tin they top each other if they are moving inwards the same management ?
1. 4 min
2. 4 min 12 sec
3. 4 min twenty sec
4. 4 min 36 sec
5. None of these
3. Two trains running on parallel lines are 510 1000 too 330 1000 long at l kmph too 38 kmph respectively. In what fourth dimension tin they top each other if they are moving inwards the same management ?
1. 4 min
2. 4 min 12 sec
3. 4 min twenty sec
4. 4 min 36 sec
5. None of these 

Model 8 :

1. Two trains running on parallel lines are 600 1000 too 900 1000 long at xl too l kmph respectively. In what fourth dimension tin they top each other if they are moving inwards contrary management ?
1. 54 sec
2. 1 min
3. 1 min 12 sec
4. 2 min
5. None of these 

Solution :

t = d/s

= (1500x18) / (190x5) = lx sec = 1 min

 Note :

• If the Distance is inwards Kms then Speed too should last inwards Kms. 
• If the Distance is inwards Meters then the Speed too should last inwards Meters. 

Practice Problems on Model 8 :

1. Two trains running on parallel lines are 600 1000 too 450 1000 long at xl too xxx kmph respectively. In what fourth dimension tin they top each other if they are moving inwards contrary management ?
1. 54 sec
2. 1 min
3. 1 min 12 sec
4. 2 min
5. None of these 
2. Tow trains running on parallel lines are 400 1000 too 500 1000 long at 22 too 23 kmph respectively. In what fourth dimension tin they top each other if they are moving inwards contrary management ?
1. 54 sec
2. 1 min
3. 1 min 12 sec
4. 2 min
5. None of these 
3. Two trains running inwards parallel lines are 600 1000 too 750 1000 long at twenty too 20.5 kmph respectively. In what fourth dimension tin they top each other if they are moving inwards contrary management ?
1. 54 sec
2. 1 min
3. 1 min 12 sec
4. 2 min
5. None of these 

Model 9 :

1. A develop of 600 1000 long moves at 54 kmph tin cross only about other develop of 750 1000 long moving inwards the same management inwards 4 1/2 min .What is the speed of the 2d develop ?
1. 36 kmph
2. 40 kmph
3. 48 kmph
4. 50 kmph
5. None of these 

Solution :

* Here the outset 1 crosses the 2d 1 (by moving inwards the same direction). So, the speed of outset develop is high

south = d/t

S1-S2 = d/t

= (1350 1000 / 270 sec) x (18/5) = 18

54-? = 18  => 36

Practice Problems on Model 9 :

1. A develop of 600 1000 long moves at 55.2 kmph tin cross only about other develop of 450 1000 long moving inwards the same management inwards 2 1/2 min. What is the speed of the 2d develop ?
1. 36 kmph
2. 40 kmph
3. 48 kmph
4. 30 kmph
5. None of these 
2. A develop of 600 1000 long moves at 76 kmph tin cross only about other develop of 480 1000 long moving inwards the same driection inwards 2 2/5 min. What is the speed of the 2d develop ?
1. 36 kmph
2. 40 kmph
3. 48 kmph
4. 50 kmph
5. None of these 
3. A develop of 900 1000 long moves at xc kmph tin cross only about other develop of 1200 1000 long moving inwards the same direction. What is the speed of the 2d develop ?
1. 36 kmph
2. 40 kmph
3. 48 kmph
4. 50 kmph
5. None of these 

Model 10 :

1. A develop 300 1000 long passes a pole inwards 25 sec. How long volition it accept to top a duad of 360 1000 long ?
1. 42 sec
2. 1 min
3. 1 min 12 sec
4. 42 sec
5. None of these 

Solutions :

s = d/t = 300/25 = 12

s =  660/12 = 55 sec

2nd Method :

300m ------> 25 sec

300+360 = 660m ----> ?

=> (660 / 300) x 25 = 55 Sec

Practice Problems on Model 10 :

1. A develop 250 1000 long passes a pole inwards twenty sec. How long volition it accept to top a duad of 275 1000 long ?
1. 54 sec
2. 1 min
3. 1 min 12 sec
4. 42 sec
5. None of these 
2. A develop 320 1000 long passes a pole inwards 24 sec. How long volition it accept to top a duad of 480 1000 long ?
1. 42 sec
2. 1 min
3. 1 min 12 sec
4. 2 min 
5. None of these 
3. A develop 270 1000 long passes a pole inwards xviii sec. How long volition it accept to top a duad of 360 1000 long ?
1. 42 sec
2. 1 min
3. 1 min 12 sec
4. 2 min
5. None of these

Model 11 :

1. A develop covers a distance inwards 24 min if it runs at 48 kmph. What should it speed last if it has to comprehend the same distance inwards xvi mins ?
1. 45 kmph
2. 60 kmph
3. 72 kmph
4. 90 kmph
5. None of these 

Solution :

24 min --------> 48 kmph

xvi min --------->  ?

=> to a greater extent than / less = (24/16) x 48 = 72 kmph

Practice Problems on Model 11

1. A develop covers a distance inwards twenty min if it runs at l kmph. What should it speed last if it has to comprehend the same distance inwards 12 min xxx sec ?
1. 45 kmph
2. 60 kmph
3. 72 kmph
4. 80 kmph
5. None of these 
2. A develop covers a distance inwards 25 min if it runs at 48 kmph. What should its speed last if it has to comprehend the same distance inwards twenty min ?
1. 45 kmph
2. 60 kmph
3. 72 kmph
4. 90 kmph
5. None of these
3. A develop covers a distance inwards xxx min if it runs at lx kmph. What should its speed last if it has to comprehend the same distance inwards twenty min ?
1. 45 kmph
2. 60 kmph
3. 72 kmph
4. 90 kmph
5. None of these  

Model 12 :

1. A automobile has to comprehend 450 kms inwards 10 hrs. It covered 2/5 of the distance inwards 3/5 of the time. At which speed should it motion to comprehend the residue of the distance inwards the residue of the fourth dimension ?  
1. 90 kmph
2. 60 kmph
3. 72 kmph
4. 90 kmph
5. None of these 

Solution :

Remaining distance = d = (1 - 2/5) x 450  = (3/5) x 450  = 270

t = (1 - 3/5) x 10 = (2/5) x 10 = 4 hrs

=> required speed = remaining distance / remaining fourth dimension =  270 / 4 = 67.5  = 67 1/2 kmph

Practice problems on Model 12 :

1. A automobile has to comprehend 550 kms inwards 10 hrs. It covered 3/5 of the distance inwards 3/4 of the time. At which speed should it motion to comprehend the residue of the distance inwards the residue of the fourth dimension ?
1. 99 kmph
2. 60 kmph
3. 72 kmph
4. 88 kmph
5. None of these 
2. A automobile has to comprehend 480 kms inwards ix hrs. It covered 2/5 of the distance inwards 2/3 of the time. At which speed should it motion to comprehend the residue of the distance inwards the residue of the fourth dimension ?
1. 99 kmph
2. 60 kmph
3. 72 kmph
4. 88 kmph
5. None of these 
3. A automobile has to comprehend 900 kmps inwards 12 hrs. It covered 9/10 of the distance inwards 7/12 of the time. At which speed should it motion to comprehend the residue of the distance inwards the residue of the fourth dimension ?
1. 99 kmph
2. 60 kmph
3. 72 kmph
4. 90 kmph
5. None of these

Model 13 :

1. A pupil walks from his menage at 2.5 kmphs too reaches his schoolhouse yesteryear v min belatedly too if he walks at 3 kmph, he volition accomplish his schoolhouse yesteryear 10 min early. What is the distance betwixt the schoolhouse too his menage ? 
1. 2.25 kms
2. 2.75 kms
3. 3.25 kms
4. 3.75 kms
5. None of these 

Solution :

=  (∆t × π s)/∆s

Distance = (Difference inwards given belatedly or early on times inwards hours x Product of the speeds)  / Difference of the speeds

= (1/4) x ((1/2)x3)/(1/2))  = 15/4                       [15 mins ---> 1/4 hr]

= 3 3/4 km

Practice Problems on Model 13 :

1. A pupil walks from his menage at 3 kmph too reaches his schoolhouse yesteryear v min belatedly too if he walks at 3.25 kmph, he volition accomplish his schoolhouse yesteryear 1 min early. What is the distance betwixt the schoolhouse too his menage ?
1.  2.25 kms
2. 2.75 kms
3. 3.25 kms
4. 3.75 kms
5. None of these
2. A pupil walks from his menage at 3 kmph too reaches his schoolhouse yesteryear xxx min belatedly too if he walks at 2 1/2 kmph, he volition accomplish his schoolhouse yesteryear 10 min xxx sec late. What is the distance betwixt the schoolhouse too his menage ?
1. 2.25 kms
2. 2.75 kms
3. 3.25 kms
4. 3.75 kms
5. None of these 
3. A pupil walks from his menage at 2 kmph too reaches his schoolhouse yesteryear xxx sec belatedly too if he walks at 3 kmph, he volition accomplish his schoolhouse yesteryear 1 min early. At which speed should he become to accomplish the schoolhouse inwards fourth dimension ?
1. 2.25 kmph
2. 2.75 kmph
3. 2.5 kmph
4. 2.4 kmph
5. None of these

Model 14 :

1. A human goes to a house at 24 kmph too returns at xl kmph. What is the average speed ?
1. 32 kmph
2. 30 kmph
3. 32.5 kmph
4. 35 kmph
5. None of these 

Solution :

If the distances are equal, Avg speed = 2AB / (A+B)

= (2 x 960) / 64 = xxx kmph

Practice Problems on Model 14

1. A human goes to a house at lx kmph too returns at 42 kmph. What is the average speed ?
1. 51kmph
2. 47 2/17 kmph
3. 48 6/17 kmph
4. 49 7/17 kmph
5. None of these 
2. A human goes to a house at lxxx kmph too returns at 56 kmph. What is the average speed ?
1. 62 kmph
2. 61 2/17 kmph
3. 65 15/17 kmph
4. 66 13/17 kmph
5. None of these 
3. A human goes to a house at 100 kmph too returns at 125 kmph. What is the average speed ? 
1. 109 2/9 kmph
2. 111 1/9 kmph
3. 113 4/9 kmph
4. 114 5/9 kmph
5. None of these

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